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A galvanic cell has the overall reaction: zn(s) 2eu(no3)3(aq)  zn(no3)2(aq) 2eu(no3)2(aq) which is the half reaction occurring at the anode

Respuesta :

kenmyna

The  half reaction that occur  at the anode is

Zn (s)→ Zn²⁺ (aq) +  2e⁻

Explanation

  • In galvanic  cell  oxidation  take   place at the  the anode.  That  is there  is  lost  of  electrons  at the anode.
  • Zn  loss two(2)  electron  to form   Zn²⁺  ion.
  • Zn  is therefore    oxidized   since it's  oxidation  move from oxidation state 0 to oxidation state  2+.

Answer: The half reaction occurring at anode is [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

Explanation:

In a chemical cell, substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

[tex]X\rightarrow X^{n+}+ne^-[/tex]

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

[tex]X^{n+}+ne^-\rightarrow X[/tex]

For the given chemical cell reaction:

[tex]Zn(s)+2Eu(NO_3)_3(aq.)\rightarrow Zn(NO_3)_2(aq.)+2Eu(NO_3)_2(aq.)[/tex]

Oxidation half reaction (anode):  [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

Reduction half reaction (cathode):  [tex]Eu^{3+}(aq.)+e^-\rightarrow Eu^{2+}(aq.)[/tex]    ( × 2 )

Here, zinc is loosing electrons and is getting oxidized and europium is gaining electrons and loosing electrons.

Hence, the half reaction occurring at anode is [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

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