qais19966p41yfx qais19966p41yfx

11-12-2018
Mathematics

contestada

find the area contained between
[tex] {y }^{2} = x[/tex]
and
[tex] y = {x}^{2} [/tex]

Respuesta :

LammettHash LammettHash

11-12-2018

The area is given by

[tex]\displaystyle\int_0^1\sqrt x-x^2\,\mathrm dx=\dfrac23x^{3/2}-\dfrac13x^3\bigg|_{x=0}^{x=1}[/tex]

so the area is

[tex]\dfrac23-\dfrac13=\dfrac13[/tex]

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