Please help me I really need it :( (-->WILL MARK BRAINLIEST<-- I ALREADY HAVE THE ANSWER FOR PART A, I JUST NEED PART B ANSWERED AND CAN YOU PLEASE EXPLAIN HOW YOU GOT YOUR ANSWER Thx :D)

Delaney would like to make a 5 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds. Let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture.

(a) What is the system that models this situation?

(b) Which of the following is a solution to the system: 2 lb peanuts and 3 lb mixture (2,3) ; 2.5 lb peanuts and 2.5 lb mixture (2.5, 2.5); 4 lb peanuts and 1 lb mixture (4,1) ? Show your work. Please help me :'(

Let p represent the number of pounds of peanuts needed to make the new mixture, and let m represent the number of pounds of the 80% almond-20% peanut mixture.

1. In m pounds of the 80% almond-20% peanut mixture there are 0.8m pounds of almonds and 0.2m pounds of peanuts.

2. When added p pounds of peanuts to m pounds of mixture, you get (p+0.2m) pounds of peanuts and 0.8m pounds of almonds.

3. In 5 pounds of the 40% almond-60% peanut mixture there are [tex]0.6\cdot 5=3[/tex] pounds of peanut and [tex]0.4\cdot 5=2[/tex] pounds of almonds.

(a) Then you get a system of two equations:

[tex]\left\{\begin{array}{l}0.8m=2\\p+0.2m=3\end{array}\right.[/tex]

(b) Solve this system. From the first equation

[tex]m=\dfrac{2}{0.8}=2.5\ pounds,[/tex]

then

[tex]p+0.2\cdot 2.5=3,\\ \\p=3-0.5,\\ \\p=2.5\ pounds.[/tex]