Consider the motion towards right as positive and motion towards left as negative.
m₁ = mass of the cart moving to right = 0.500 kg
v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s
m₂ = mass of cart moving to left = 0.800 kg
v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s
initial momentum of the system of carts before the collision is given as
P₁ = m₁ v₁ + m₂ v₂
P₁ = (0.500) (2.2) + (0.800) (- 1.1)
P₁ = 0.22 kg m/s
P₂ = momentum of system of carts after collision
As per conservation of momentum,
Momentum of system of carts after collision = Momentum of system of carts before collision
P₂ = P₁
P₂ = 0.22 kg m/s
The final momentum of the system before the collision is 1.02 kg-m/s.
Given data:
The mass of first cart is, m = 0.500 kg.
The initial velocity of first cart before collision is, u = 2.20 m/s.
The mass of another cart is, m' =0.800 kg.
The initial velocity of second cart before collision is, u' = -1.10 m/s. (Negative sign shows the opposite direction)
Use the conservation of linear momentum, which says that momentum of a system before collision is equal to the momentum of the system after the collision.
Total momentum before collision = Total momentum after collision
[tex]P_{i} = P_{f}\\\\mu+m'u' = P_{f}\\\\P_{f}=(0.500 \times 2.20)+(0.800 \times -0.100)\\\\P_{f}=1.02 \;\rm kg-m/s[/tex]
Thus, we can conclude that the final momentum of the system before the collision is 1.02 kg-m/s.
Learn more about the conservation of linear momentum here:
https://brainly.com/question/3920210
