W = work done by the spring on the toy car = 196 Joules
m = mass of the toy car = 2 kg
v₀ = initial velocity of the car when at rest = 0 m/s
v = final velocity of the car after spring does work on it = ?
According to work-change in kinetic energy, net work done on an object is same as the change in kinetic energy of the object . hence
Net work done = Final kinetic energy - initial kinetic energy
W = (0.5) m (v² - v₀²)
inserting the values
196 = (0.5) (2) (v² - (0)²)
v² = 196
v = sqrt(196)
v = 14 m/s
The final velocity of the toy cars is 14 m/s
Given data:
The mass of toy car is, m = 2 kg.
The work performed by the spring is, W = 196 J.
In the given problem, the work done by the spring provides the necessary kinetic energy to the toy car. Therefore, work -energy theorem can be applied.
According to work-energy theorem, the work done on an objects is equal to the change in kinetic energy of the object .So,
W = KE
Solving as,
[tex]W = \dfrac{1}{2} mv^{2} \\\\196=\dfrac{1}{2} \times 2 \times v^{2}\\v = 14 \;\rm m/s[/tex]
Thus, we can conclude that the final velocity of the toy cars is 14 m/s .
Learn more about the kinetic energy from here;
https://brainly.com/question/17858145
