[02.06] The label on the car's antifreeze container claims to protect the car between −30°C and 130°C. To convert Celsius temperature to Fahrenheit temperature, the formula is C = 5 over 9 (F − 32). Write and solve the inequality to determine the Fahrenheit temperature range at which this antifreeze protects the car.

Respuesta :

Answer:

It is given that the label on the car's antifreeze containers claims to protect the car between [tex]-30^{\circ} C[/tex] and  [tex]130^{\circ} C[/tex].

Convert Celsius temperature to Fahrenheit temperature;

Using the formula:

[tex]C = \frac{5}{9}(F-32)[/tex]  

Multiply both sides by [tex]\frac{9}{5}[/tex] we get;

[tex]\frac{9}{5}C =\frac{5}{9}(F-32) \times \frac{9}{5}[/tex]

Simplify:

[tex]\frac{9}{5}C = F-32[/tex]

Add 32 to both sides of an equation:

[tex]\frac{9}{5}C +32= F-32+32[/tex]

Simplify:

[tex]\frac{9}{5}C +32= F[/tex]                      ......[1]

Substitute the value  [tex]-30^{\circ} C[/tex] in [1];

[tex]F = \frac{9}{5} \cdot (-30^{\circ} ) +32[/tex]

or

[tex]F= 9 \cdot (-6)+32 =-54+32 = -22 ^{\circ}[/tex]

Similarly, Substitute the value [tex]130^{\circ} C[/tex] in [1] we have;

[tex]F = \frac{9}{5} \cdot (130^{\circ} ) +32[/tex]

or

[tex]F= 9 \cdot (26)+32 =234+32 = 266 ^{\circ}[/tex]

then, we have [tex]-22^{\circ}<F<266^{\circ}[/tex]

Therefore, the inequality  [tex]-30<\frac{5}{9}(F-32) < 130[/tex]  that determine the Fahrenheit temperature range at which this antifreeze protects the car is;  [tex]-22<F<266[/tex]