[tex] \sqrt{-12} - \sqrt{-48} = [/tex]
[tex] = i\sqrt{12} - i\sqrt{48} [/tex]
[tex] = i\sqrt{4 \times 3} - i\sqrt{16 \times 3} [/tex]
[tex] = 2i\sqrt{3} - 4i\sqrt{3} [/tex]
[tex] = -2i\sqrt{3} [/tex]
Answer: [tex] -2i\sqrt{3} [/tex]
[tex]i=\sqrt{-1}\\\\\sqrt{-12}=\sqrt{(4)(-1)(3)}=\sqrt4\cdot\sqrt{-1}\cdot\sqrt{3}=2i\sqrt3\\\\\sqrt{-48}=\sqrt{(16)(-1)(3)}-=\sqrt{16}\cdot\sqrt{-1}\cdot\sqrt3=4i\sqrt3\\\\\sqrt{-12}-\sqrt{-48}=2i\sqrt3-4i\sqrt3=\boxed{-2i\sqrt3}[/tex]
