Answer:- 4.36 kPa
Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
Where the subscripts 1 and 2 are representing initial and final quantities.
From given data:
[tex]P_1[/tex] = 1.049 kPa
[tex]P_2[/tex] = ?
[tex]T_1[/tex] = 7.39 K
[tex]T_2[/tex] = 30.70 K
For final pressure, the equation could also be rearranged as:
[tex]P_2=\frac{P_1T_2}{T_1}[/tex]
Let's plug in the values in it:
[tex]P_2=\frac{1.049kPa(30.70K)}{7.39K}[/tex]
[tex]P_2[/tex] = 4.36 kPa
So, the new pressure of the gas is 4.36 kPa.
