The fomula of a volume of a cylinder:
[tex]V=\pi r^2H[/tex]
Cylinder A:
We have r = 1m and H = 4m. Substitute:
[tex]V_A=\pi(1^2)(4)=\pi(1)(4)=4\pi\ m^3[/tex]
Cylinder B:
We have r = 3m and H = 12m. Substitute:
[tex]V_B=\pi(3^2)(12)=\pi(9)(12)=108\pi\ m^3[/tex]
The ratio:
[tex]\dfrac{V_A}{V_B}=\dfrac{4\pi}{108\pi}=\dfrac{4}{108}=\dfrac{4:4}{108:4}=\dfrac{1}{27}=1:27[/tex]
