Respuesta :

Ionic equation:

[tex]\text{H}_2\text{PO}_4^{-} + \text{HAsO}_4^{2-} \to \text{HPO}_4^{2-} + \text{H}_2\text{AsO}_4^{-}[/tex]

The acid and base in a conjugate pair differ by only one proton [tex]\text{H}^{+}[/tex]. The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.

[tex]\text{H}_2\text{PO}_4^{-}[/tex] loses one proton to produce [tex]\text{HPO}_4^{2-}[/tex] in this reaction.

[tex]\text{H}_2\text{PO}_4^{-} \to \text{H}^{+} + \text{HPO}_4^{2-}[/tex]

Meanwhile, [tex]\text{HAsO}_4^{2-}[/tex] gains one proton to form [tex]\text{H}_2\text{AsO}_4^{-}[/tex].

[tex]\text{HAsO}_4^{2-} + \text{H}^{+} \to \text{H}_2\text{AsO}_4^{-}[/tex]

Therefore

  • [tex]\text{H}_2\text{PO}_4^{-}[/tex] is the conjugate acid  [tex]\text{HPO}_4^{2-}[/tex], its conjugate base.
  • [tex]\text{HAsO}_4^{2-}[/tex] is the conjugate base of [tex]\text{H}_2\text{AsO}_4^{-}[/tex], its conjugate acid.

Ionic equation:




The acid and base in a conjugate pair differ by only one proton . The acid loses one proton to produce a conjugate base, whereas the base gains a proton to produce its conjugate acid.


loses one proton to produce  in this reaction.




Meanwhile,  gains one proton to form .




Therefore


  • is the conjugate acid  , its conjugate base.
  • is the conjugate base of , its conjugate acid.