The heat of vaporization of liquid is 1340 joules per gram. What is the minimum number of joules needed to change 40.0 grams of liquid to vapor at the boiling point?
A) 33.5
B)1340
c)3,280
D) 53600

Respuesta :

i think is c ¡I THINK!

The minimum number of joules needed to change 40.0 g of the liquid to vapor at the boiling point is 53600 J

The correct answer to the question is Option D. 53600 J

From the question given above, the following data were obtained:

Heat of Vaporisation (Hᵥ) = 1340 J/g

Mass (m) = 40 g

Heat (Q) =?

The heat needed can be obtained as follow:

Q = m•ΔHᵥ

Q = 40 × 1340

Q = 53600 J

Therefore, 53600 J of heat is needed change 40 g of the liquid to vapor at the boiling point.

Thus, Option D. 53600 J gives the correct answer to the question.

Learn more: https://brainly.com/question/16990064