Answer: Option (d) is the correct answer.
Explanation:
Oxidation number is defined as the number located at the top of the symbol of an atom by either gain or loss of electrons when it chemically combines with another atom.
In [tex]H_{2}SO_{4}[/tex] compound, the oxidation number of a hydrogen atom is +1 and oxidation number of an oxygen atom is -2.
Therefore, let the oxidation number of sulfur is x and calculate its value as follows.
2(1) + x + 4(-2) = 0
x = +6
Thus, we can conclude that the oxidation number of sulfur in sulfuric acid is +6.
