What is the volume of a sphere with a radius of 6 units
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The correct answer is: [B]: " 288 [tex]\pi[/tex] units³ " .
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Explanation:
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The formula for the volume, "V" , of a sphere is:
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→ V = [tex]\frac{4}{3} * \pi * r^{3}[/tex] ;
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in which:
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V = volume (in "units³ " ; or, write as "cubic units" ).
in our case, we our not given specific units; but simply "units" ;
as such, the volume is expressed as: "units³ " ; or "cubic units".
Note: When calculating the volume of a solid:
I f not given ANY type of units — {or even given the word "units" / for the type of units / as in this particular question/problem} — as the type of units ;
→ then, we express the "volume" of a solid — in:
"cubic units" ; or, " units³ " .
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So: The volume, "V" ; for a "sphere" ; can be calculated using the formula:
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→ V = [tex]\frac{4}{3} * \pi * r^{3}[/tex] ;
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in which:
→ V = volume {of the "sphere" ; in: ["units³ "] ; as aforementioned;
→ [tex]\pi[/tex] ≈ 3.14 ;
{ Note: For our purposes, we shall use the number; " 3.14 " ; as an approximation for " [tex]\pi[/tex] " .}.
→ r = "radius" = " 6 units " ; ← (given) ;
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So, let us plug in these values into the formula;
→ to solve for the volume, "V" ; of the sphere:
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→ V = [tex]\frac{4}{3}[/tex] * [tex]\pi[/tex] * r³ ;
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→ V = [tex]\frac{4}{3} * [tex]\pi[/tex] * (6 units)³ ;
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Note: (6 units)³ = 6³ * (units)³ ;
→ {since: " (ab)ⁿ = aⁿ bⁿ ".}. .
→ 6³ * (units)³ = ?? " ;
= 6³ = 6 * 6 * 6 = 36 * 6 = 216 .
(or: Use calculator: " 6³ = 216 " .).
→ 6³ * (units)³ = 216 units³ .
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So: V = [tex]\frac{4}{3}[/tex] * 3.14 * (216 units³) = _?_ units³ ?? ;
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→ V = [ [tex](\frac{4}{3}) * (3.14) * (216)[/tex] ] units³ ;
= 904.3200000000000072 units³ . (used calculator).
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Now, upon examining the 4 (four) answer choices provided, we notice that "none" of them give this very [directly aforementioned] answer.
Furthermore, upon examining examining the 4 (four) answer choices provided, we notice that EACH answer choice does, in fact, list an answer with units of: " units³ " .
However, note that for EACH of the 4 (four) answer choices provided, we notice that ALL of the "answer choices" provided; for the "volume" of the "sphere" are given in terms of: " [tex]\pi[/tex] " .
So, if we take our calculated answer for the "volume" of the "sphere", which, as aforementioned, is:
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→ V = " 904.3200000000000072 units³ " .
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→ AND: We divide that numeric value by "[tex]\pi[/tex]" ;
→ {that is: divide that numeric value by the approximation
for: " [tex]\pi[/tex] " ;
→ that is; divide that numeric value by: " 3.14 " ;
→ We can find a "coefficient" of sorts, to:
" [tex]\pi[/tex] " ;
→ when " [tex]\pi[/tex] " ; is written as a symbol .
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If this number is very close to one of the 4 (four) answer choices provided;
→ that is, close to the "coefficient" of: " [tex]\pi[/tex] " ;
→ when " [tex]\pi[/tex] " ; is written as a symbol ;
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→ Then this should reflect the correct answer choice.
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Now, let us calculate; as follows:
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→ " 904.3200000000000072 " ;
÷ " 3.14 "
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to get:
= " 288.000000000000002293 " ;
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→ which corresponds to:
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→ Answer choice: [B]: " 288 [tex]\pi[/tex] units³ " .
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Source used: "Web 2.0 scientific calculator." Online Scientific Calculator. 2018. Web. Date accessed/used: 14 Nov 2018 .
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