We want to write the equation of a line parallel to y = 3x - 2, such that it passes through (-6, -11).
The line is: y = 3x + 7
Two lines are parallel if have the same slope and different y-intercept, remember that in the general line:
y = a*x + b
a is the slope and b is the y-intercept.
The given line is:
y = 3x - 2
So the slope is a = 3, then the other line will be something like:
y = 3x + c
To get the value of c, we use the fact that this line passes through (-6, -11).
We can replace these values in the line equation to get:
-11 = 3*-6 + c
-11 = -18 + c
-11 + 18 = c = 7
Then the equation of the line is:
y = 3x + 7
If you want to learn more, you can read:
https://brainly.com/question/16701300
