The slope-intercept form:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the slope [tex]m=-\dfrac{1}{4}\to y=\dfrac{1}{4}x+b[/tex]
and point (8, -3). Substitute:
[tex]-3=-\dfrac{1}{4}(8)+b[/tex]
[tex]-3=-2+b[/tex] add 2 to both sides
[tex]-1=b\to b=-1[/tex]
Answer: [tex]y=-\dfrac{1}{4}x-1[/tex]
The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
Substitute:
[tex]y-(-3)=-\dfrac{1}{4}(x-8)\\\\\boxed{y+3=-\dfrac{1}{4}(x-8)}\to\boxed{D.}[/tex]}
