contestada

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0.8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in Table A of your Student Guide. When the mass of the bottle is 0.125 kg, the KE is kg m2/s2. When the mass of the bottle is 0.250 kg, the KE is kg m2/s2. When the mass of the bottle is 0.375 kg, the KE is kg m2/s2. When the mass of the bottle is 0.500 kg, the KE is kg m2/s2.

Respuesta :

kinetic energy is given as

KE = (0.5) m v²

given that : v = speed of the bottle in each case =  4 m/s

when m = 0.125 kg

KE = (0.5) m v² =  (0.5) (0.125) (4)² = 1 J

when m = 0.250 kg

KE = (0.5) m v² =  (0.5) (0.250) (4)² = 2 J

when m = 0.375 kg

KE = (0.5) m v² =  (0.5) (0.375) (4)² = 3 J

when m = 0.0.500 kg

KE = (0.5) m v² =  (0.5) (0.500) (4)² = 4 J

Lanuel

a. When the mass of the bottle is 0.125 kg, its kinetic energy is [tex]1 \;Kgm^2/s^2[/tex].

b. When the mass of the bottle is 0.250 kg, its kinetic energy is [tex]2 \;Kgm^2/s^2[/tex].

c. When the mass of the bottle is 0.375 kg, its kinetic energy is [tex]3 \;Kgm^2/s^2[/tex].

d. When the mass of the bottle is 0.500 kg, its kinetic energy is [tex]4 \;Kgm^2/s^2[/tex].

Given the following data:

  • Height = 0.8 meters
  • Velocity = 4 m/s.

To find the kinetic energy of the bottle:

Kinetic energy refers to an energy that is possessed by a physical object or body due to its motion.

Mathematically, kinetic energy is calculated by using the formula;

[tex]K.E = \frac{1}{2} MV^2[/tex]

Where:

  • K.E is the kinetic energy.
  • M is the mass of an object.
  • V is the velocity of an object.

a. When the mass of the bottle is 0.125 kg:

[tex]K.E = \frac{1}{2} \times 0.125 \times 4^2\\\\K.E = 0.0625 \times 16[/tex]

Kinetic energy = [tex]1 \;Kgm^2/s^2[/tex].

b. When the mass of the bottle is 0.250 kg:

[tex]K.E = \frac{1}{2} \times 0.250 \times 4^2\\\\K.E = 0.125 \times 16[/tex]

Kinetic energy =  [tex]2 \;Kgm^2/s^2[/tex].

c. When the mass of the bottle is 0.375 kg:

[tex]K.E = \frac{1}{2} \times 0.375 \times 4^2\\\\K.E = 0.1875 \times 16[/tex]

Kinetic energy =  [tex]3 \;Kgm^2/s^2[/tex].

d. When the mass of the bottle is 0.500 kg:

[tex]K.E = \frac{1}{2} \times 0.500 \times 4^2\\\\K.E = 0.250 \times 16[/tex]

Kinetic energy =  [tex]4 \;Kgm^2/s^2[/tex].

Read more: https://brainly.com/question/23153766

Otras preguntas