Answer: [tex]n=-\frac{42}{5}[/tex]
Step-by-step explanation:
1. You have the following equation given in the problem above:
[tex]\frac{2n}{3}=n+\frac{14}{5}[/tex]
2. You must solve for n, as following:
[tex]\frac{2n}{3}=n+\frac{14}{5}\\\frac{2n}{3}-n=\frac{14}{5}\\\frac{2n-3n}{3}=\frac{14}{5}\\\frac{-n}{3}=\frac{14}{5}\\-n=\frac{3*14}{5}\\-n=\frac{42}{5}\\n=-\frac{42}{5}[/tex]
3. Then, the result of the equation is:
[tex]n=-\frac{42}{5}[/tex]
