Given:
To Find:
The regular price of the monthly fee 'r'
Solution:
The equation can be framed as
[tex](r-\frac{50}{100}.r)+8.25=39.25\\\frac{50}{100}.r+8.25=39.25\\\frac{r}{2}+8.25=39.25\\\frac{r}{2}=31\\r=(31)(2)=62[/tex]
And, the regular price of the monthly fee is $62.
Calculation:
We know that 10 students took the offer and the yoga studio collected $392.50. This means, using the Unitary Method, the studio has collected $(392.50/10) = $39.25 per student.
Now, if r denotes the regular price of the monthly fee, the offer runs a 50% discount on r.
So, the discounted price should be $(r - 50% of r) i.e., [tex]r-\frac{50}{100}.r[/tex]
We must add to this the one time processing fee of $8.25
Therefore, the total price paid by one student would be
[tex](r-\frac{50}{100}.r)+8.25[/tex]
This must be equal to $39.25 as we have calculated this to be the amount collected by the yoga studio per person.
So, the equation can be framed as
[tex](r-\frac{50}{100}.r)+8.25=39.25\\\frac{50}{100}.r+8.25=39.25\\\frac{r}{2}+8.25=39.25\\\frac{r}{2}=31\\r=(31)(2)=62[/tex]
Thus, the regular price of the monthly fee is $62.