PLZ HELP
what is the equation of a line, in point-slope form, that passes through (5,-3) and has a slope of 2/3

A.
y + 5 = 2/3 (x - 3)

B.
y - 3 = 2/3 (x + 5)

C.
y - 5 = 2/3 (x + 3)

D.
y + 3 = 2/3 (x - 5)



Respuesta :

point slope form

y-y1 = m(x-x1)

y--3 = 2/3(x-5)

y+3=2/3(x-5)

Choice D


D. is the correct answer.

Slope intercept form: [tex]y=mx+b[/tex]

m: represents the slope and is constant.

b: represents the y-intercept.

Given the following equation, locate the slope and y-intercept of the line.

For example: [tex]y=-\frac{1}{2}x-8[/tex]

The slope: m= [tex]-\frac{1}{2}[/tex]

The y-intercept: b= [tex]-8[/tex]

Point slope form: → [tex]slope=\frac{y^2-y^1}{x^2-x^1}[/tex]

[tex]m=\frac{y^2-y^1}{x^2-x^1}[/tex]

Used: rise/run

[tex]m=\frac{rise}{run}[/tex]

Given:  

[tex](y^1)=m(x^1)[/tex]

[tex]y-3=\frac{2}{3}(x-5)[/tex]

Then you add by the variable on y-3.

[tex]\boxed{y+3=2/3(x-5)}[/tex]

Hope this helps!

Thanks!

Have a great day!