Respuesta :
Answer:
- BC — y = -3.5x -15
- DE — y = -0.5x -3
- FG — (no matching equation shown) y = -2x + b
- HI — y = 1.25x +4
- JK — (no matching equation shown) y = -0.375x + b
- LM — y = 5x +19
Explanation:
Since you only want to identify the parallel line, you only need to compute the slope between the two points. That is ...
... m = (y2 -y1)/(x2 -x1)
The line of interest will have this slope value as its x-coefficient.
BC: the slope is (-5-2)/(7-5) = -7/2 = -3.5 . . . . matches y = -3.5x -15
DE: the slope is (9-6)/(5-11) = 3/-6 = -0.5 . . . . matches y = -0.5x -3
FG: the slope is (-8-12)/(3-(-7)) = -20/10 = -2 . . . . no match
HI: the slope is (9-4)/(8-4) = 5/4 = 1.25 . . . . matches y = 1.25x +4
JK: the slope is (8-2)/(-9-7) = 6/-16 = -0.375 . . . . no match
LM: the slope is (-12-(-7))/(4-5) = -5/-1 = 5 . . . . matches y = 5x +19
Answer:
BC — y = -3.5x -15
DE — y = -0.5x -3
FG — (no matching equation shown) y = -2x + b
HI — y = 1.25x +4
JK — (no matching equation shown) y = -0.375x + b
LM — y = 5x +19
Step-by-step explanation: