Greg drove to school at 30 mph to drop off his friend’s car. He then jogged home at 6 mph. If the entire trip too k him 1 hour, how far does he live from school?

Respuesta :

5 miles

using the formula

time = [tex]\frac{distance(d)}{speed}[/tex], then his distance can be calculated

[tex]\frac{d}{30}[/tex] + [tex]\frac{d}{6}[/tex] = 1

[tex]\frac{d}{30}[/tex] + [tex]\frac{5d}{30}[/tex] = 1

[tex]\frac{6d}{30}[/tex] = 1 ( multiply both sides by 30 )

6d = 30 ( divide both sides by 6 )

d = 5

He lives 5 miles from school


Answer: He lives 5 miles from school.

Solution:

Let distance between school and home be x miles.

Grey drove to school at speed = 30 mph

Distance between school and home = x mile

Formula used: [tex] Time=\frac{Distance}{Speed}[/tex]

Time taken by Grey from home to school  [tex] T_1=\frac{x}{30}[/tex]

Grey jogged to home at speed = 6 mph

Distance between school and home = x mile

Formula used: [tex] Time=\frac{Distance}{Speed}[/tex]

Time taken by Grey from home to school  [tex] T_2=\frac{x}{6}[/tex]

Grey took 1 hour for entire trip.

Therefore, [tex]T_1+T_2=1[/tex]

[tex] \frac{x}{30}+ \frac{x}{6}=1[/tex]

[tex] \frac{x}{30}+ \frac{5x}{30}=1[/tex]

[tex] \frac{6x}{30}=1[/tex]

we get , x=5 miles.

He lives 5 miles from school.