The temperature of a gas increased from 398K to 455K inside of a rigid container. If the original pressure of the gas was 1.22atm, what will the pressure of the gas after the temperature change?

Respuesta :

According to pressure law, at a constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin scale.

[tex]\frac{P1}{T1} =\frac{P2}{T2}[/tex]

Here, P1 = Initial pressure of the gas = 1.22 atm

T1 = Initial temperature of the gas = 398 K

T2 = Final temperature of the gas = 455 K

P2 = Final pressure of the gas = ?

Therefore,

[tex]P2 = \frac{(P1)(T2)}{T1} =  \frac{(1.22)(455)}{398} atm = 1.39 atm = 1.4 atm[/tex]

Therefore, the required pressure of the gas after the change in temperature is 1.4 atm.