Ice melts at a constant temperature of 0° C
heat absorbed by ice while melting = mass of ice melted × Ice's heat of fusion ------------------ eq1
Mass of ice = 450g
need to calculate 2/3 of its melted :- 2/3 of 450 = 300g
mass of ice melted = 300g and ice's heat of fusion( 333.55J/gm)
(value of ice's heat of fusion is universal constant)
from eq1 :- Heat absorbed = 300 × 333.55 = 100065 J => 100.065Kj
