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If a Geiger counter that is 1 m away from a small source reads 50 counts per minute, what will its reading be 2 m from the source?

Respuesta :

as the amount of radiation received is proportional to 1/d^2

2m from source


for 1m readings are 50 count per minute


for 2m =   50 / (2)^2

                   50 / 4   =  12.5 count per minute

sebassandin

Answer:

[tex]12.5counts/min[/tex]

Explanation:

Hello,

In this case, the radiation from a point source follows an inverse-square law wherein the quantity of radiation is proportional to 1/d², where d is distance. Therefore, 2 m away from the source, the counts will be:

[tex]Counts/min=\frac{50counts/min}{2^2} =12.5counts/min[/tex]

Best regards.

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