Answer:
Let the points for School X be a
and for the School Y be b.
From the given condition : School X has 8 more points than school Y.
we have;
a = b+8 ......[1]
Also, School X has 3 times as many points as school Y, which implies
a = 3b ......[2]
Substitute the value a of [2] in [1]; to solve for b;
we have;
3b=b+8
Subtract b from both sides of an equation we get;
3b-b=b+8-b
Simplify:
2b=8
Divide by 2 from both sides of an equation we get;
[tex]\frac{2b}{2}= \frac{8}{2}[/tex]
Simplify:
b=4
Substitute the value of b in equation [2];
[tex]a=3 \cdot 4 = 12[/tex]
Therefore, School X has 12 points and School Y has 4 points.
