Answer:- Volume decreases by a factor of 1.15.
Solution:- At constant pressure, volume of the gas is directly proportional to the the kelvin temperature.
The equation is written as:
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
where, [tex]V_1[/tex] is the volume at initial temperature [tex]T_1[/tex] and [tex]V_2[/tex] is the volume at final temperature [tex]T_2[/tex] .
Temperature must be in kelvins. So, let's convert both the temperatures to kelvin.
To convert degree C to kelvin we add 273.
So, [tex]T_1[/tex] = 100 + 273 = 373 K
[tex]T_2[/tex] = 50 + 273 = 323 K
The equation could also be written as:-
[tex]\frac{V_1}{V_2}=\frac{T_1}{T_2}[/tex]
[tex]\frac{V_1}{V_2}=\frac{373}{323}[/tex]
[tex]\frac{V_1}{V_2}[/tex] = 1.15
From here we could say that the volume decreases by a factor of 1.15.
For example if the initial volume [tex]V_1[/tex] is 1 L then final volume [tex]V_2[/tex] will be [tex]\frac{1L}{1.15}[/tex] that is 0.87 L.
