PLEASE HELP ME FIGURE THIS OUT 1..
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Answer: π/6
Step-by-step explanation:
sec θ = [tex]\frac{2}{\sqrt{3}}[/tex]
sec = [tex]\frac{1}{cos}[/tex]
⇒ [tex]\frac{1}{cos}[/tex] = [tex]\frac{2}{\sqrt{3}}[/tex]
⇒ cos θ = [tex]\frac{\sqrt{3}}{2}[/tex]
Since it is an acute angle, then 0° > θ > 90°
Look at the Unit Circle to find that cos θ = [tex]\frac{\sqrt{3}}{2}[/tex] at π/6
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Answer: -300°
Step-by-step explanation:
Set up the proportion:
[tex]\frac{\pi }{180} = \frac{-5\pi} {3x}[/tex]
Cross multiply and solve:
π(3x) = 180(-5π)
x = [tex]\frac{180(-5\pi)}{3\pi}[/tex]
x = 60(-5)
x = -300