Respuesta :
Answer:- 6.19 g of water will form.
Solution:- The given balanced equation is:-
[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(l)[/tex]
From this equation, there is 1:2 mol ratio between oxygen and water. It means there will be two moles of water produced for each mol of oxygen consumed.
Let's convert given grams of oxygen to moles on dividing the grams by molar mass (32.0 g per mol) and multiply the moles of oxygen by mol ratio to get the moles of water and finally multiply by molar mass of water(18.02 g per mol) to get the grams of water formed.
[tex]5.50gO_2(\frac{1molO_2}{32.0gO_2})(\frac{2molH_2O}{1molO_2})(\frac{18.02gH_2O}{1molH_2O})[/tex]
= [tex]6.19gH_2O[/tex]
So, 6.19 g of water will form when 5.50 g of oxygen reacts with excess of hydrogen gas.
