Respuesta :
The gravitational force between two masses act along the line that connects the two masses and it is an attractive force. The value of this force is directly proportional with the values of the two masses [m_1] and [m_2] and inversely proportional with the square of the distance between the two objects.
[F = G*(m_1*m_2)/R^2]
Here above G is the gravitational constant.
With the values given in the problem text one has
[F = 6.67*10^-11*(70*2000)/1^2...]
Taking into account the definition of gravitational, the force between the two objects is 9.338×10⁻⁶ N.
The gravitational force is the force of mutual attraction that two objects with mass experience. That is to say, bodies, by the simple fact of having mass, experience a force of attraction towards other bodies with mass, called gravitational force or gravitational force.
The gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.
Mathematically it is expressed as follows:
[tex]F=G\frac{Mm}{r^{2} }[/tex]
where:
- G is the universal constant of gravitation, G = 6.67 · 10⁻¹¹ N·m²/kg²
- M and m are the masses of the interacting bodies
- r is the distance that separates them.
In this case, you know::
- M= 70 kg
- m= 2000 kg
- r= 1 m
Replacing:
[tex]F=6.67x10^{-11} \frac{N.m^{2}}{kg^{2} } \frac{70 kgx2000 kg}{(1 m)^{2} }[/tex]
Solving:
F= 9.338×10⁻⁶ N
Finally, the force between the two objects is 9.338×10⁻⁶ N.
Learn more:
- https://brainly.com/question/21297378?referrer=searchResults
