PLEASE HELP!

You've determined that, in a direct variation problem, the constant of variation (k) is 1/8. What is the value of y when x is 12? Just type the value of y (a number). If it's an integer, type the integer. Otherwise, write it as a fraction in simplest form.

Respuesta :

ANSWER


When the value of x is 12, then,



[tex]y=1\frac{1}{2} [/tex]


EXPLANATION


The statement, y varies directly as x is written nathematically as [tex]y \propto x[/tex]


If we introduce the constant of proportionality, then we can write the equation,


[tex]y=kx[/tex]


where k is the constant of proportionality. It is also called the constant of variation.




If

[tex]k=\frac{1}{8}[/tex], then the direct variation equation becomes.





[tex]y=\frac{1}{8}x[/tex]




When


[tex]x=12[/tex], then



[tex]y=\frac{1}{8}\times 12[/tex]



This simplifies to


[tex]y=\frac{3}{2} [/tex]




[tex]y=1\frac{1}{2} [/tex]




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