The correct answer is B. [tex]1.6\times 10^{-6}[/tex]
Explanation
The question provides us with information about the concentration of [tex][OH^{-} ][/tex] and we are supposed to use this information to find the [tex][H^{+} ][/tex] concentration. The pH of a solution gives us information about [tex][H^{+} ][/tex]
If we the reaction is in equilibrium and with standard conditions of 25°C, then pH is given by the formula
[tex]14 = pH + pOH\\\implies pH= 14 - pOH= 14-8.20= 5.8[/tex].
Once we find the pH we use the relationship [tex]pH= -log[H^{+} ][/tex], then the [tex][H^{+} ][/tex],is given by
[tex]pH = -log[H^{+} ]\\\implies [H^{+} ]= 10^{-pH} = 10^{-5.8}= 1.58 \times 10^{-6}[/tex]
