The amount of force required to lift the object over the given distance is 70 Newton.
Given the data in the question;
Work done; [tex]W = 280J[/tex]
Displacement of the object; [tex]d = 4.0m[/tex]
Force used; [tex]F=\ ?[/tex]
Work done is the measure of energy transfer that takes place when an external force moves an object over a certain distance.
Work done = Force × Distance
[tex]Work\ done = F * d[/tex]
We substitute our given data into this equation and solve for "F"
[tex]280J = F * 4.0m\\\\F = \frac{280J}{4.0m}\\\\F = \frac{280kg.m^2/s^2}{4.0m}\\\\F = 70kg.m/s*2\\\\F = 70N[/tex]
Therefore, the amount of force required to lift the object over the given distance is 70 Newton.
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