The pseudocode to find the sum of all integers that are multiples of 9, from 1 to 250.
totalSum = 0
for i from 1 to 250{
if i is divided by 9 and remainder is 0{
totalSum = totalSum + i;
}
}
print(totalSum)
in python language the code will be
totalSum = 0
for i in range(1,250):
if i%9==0:
totalSum += i
If you will run the program , the answer would be 3402.
Answer:
To find the sum of all integers that are multiples of 9 from 1 to 250, first initialize the total sum with zero (0). After this, define for loop from 1 to 250 so that all the integers from 1 to 250 will be checked. Now, define the condition if the number is divisible by 9 or not. If number is divisible by 9 then add the integer with total sum. This process continues till the number 250. Thus, the total sum is the sum of the multiples of 9 from 1 to 250.
Further Explanation:
Following is the python program to calculate sum of the multiples of 9 from 1 to 250.
Code:
sum = 0
for i in range(1,250):
if i%9==0:
sum = sum+ i
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Answer details:
Keywords:
Python, JAVA, C++, C, compute, sum, all integers, multiples of 9, from 1 to 250, result, text box, below, sum, range
