Respuesta :

kenmyna

The  grams   of NaCl  that are required  to  make  150.0 ml of  a  5.000 M  solution is  43.875 g


calculation

Step 1:calculate  the  number of moles

moles =  molarity  x volume  in L

volume  = 150 ml / 1000 = 0.15 L

= 0.15 L  x 5.000  M  = 0.75  moles

Step 2:  calculate mass

mass =  moles x  molar mass

molar mass  of NaCl = 23 + 35.5 = 58.5 mol /L


mass is therefore =0.75  moles  x 58.5  mol /l =43.875 g

Answer : The mass of NaCl required is 43.83 g.

Solution : Given,

Volume of solution = 150 ml

Molarity of solution = 5 mole/L

Molar mass of NaCl = 58.44 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of a solution.

Formula used :

[tex]Molarity=\frac{w_{solute}\times 1000}{M_{solute}\times V_{solution(L)}}[/tex]

where,

[tex]{w_{solute}[/tex] = mass of solute

[tex]{M_{solute}[/tex] = molar mass of solute

[tex]{V_{solution(L)}[/tex] = volume of solution in liter

In this question, the solute is NaCl.

Now put all the given values in this formula, we get

[tex]5mole/L=\frac{w_{solute}\times 1000}{58.44g/mole\times 150L}[/tex]

By rearranging the term, we get the mass of NaCl.

[tex]w_{solute}=43.83g[/tex]

Therefore, the mass of solute (NaCl) required is 43.83 g.

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