The number of grams of NaCl required to make 150.0 ml of a 5.000m solution is 43.875 grams
calculation
Step 1: calculate moles of NaCl
moles= molarity x volume in liters
volume in liters = 150.0 ml/1000= 0.15 l
moles is= 5.000mol/l x0.15 l =0.75 moles
Step2 : find mass
mass= moles x molar mass
molar mass of NaCl= 23 +35.5 = 58.5 g/mol
mass= 0.75 moles x58.5 g/mol = 43.875 grams
