As the equation of the line with two points (a,b) and (c,d) is given by
(x-a)/(c-a) = (y-b)/(d-b)
We have
(x-7)/(-4-7) = (y-5)/(-1-5)
(x-7)/(-11) = (y-5)/(-6)
6(x-7) = 11(y-5)
6x-42=11y -55
11y= 6x-42+55
11y = 6x+13
y=(6/11)x + (13/11) is the respective slope intercept form of it
Answer: [tex](y-5)=\dfrac{-6}{-11}(x-7)[/tex]
Step-by-step explanation:
We know that the point slope form of a line that passes through two points (a,b) and (c,d) is given by :-
[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]
Similar;y , the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) will be :-
[tex](y-5)=\dfrac{-1-5}{-4-7}(x-7)[/tex]
[tex](y-5)=\dfrac{-6}{-11}(x-7)[/tex]
Hence, the equation in point-slope form of the line that passes through the points (7, 5) and (−4, −1) is given by :-
[tex](y-5)=\dfrac{-6}{-11}(x-7)[/tex]
