Answer: [tex]4\dfrac{5}{16}\text{ inches}[/tex]
Step-by-step explanation:
Given : A welder must cut a piece of metal so that it fits tightly into its spot.
The size of the metal which he cut off= [tex]\dfrac{9}{16}\text{ inch}[/tex]
The new size of the metal after he cut off a piece = [tex]3\dfrac{3}{4}\text{ inch}[/tex]
[tex]=\dfrac{15}{4}\text{ inches}[/tex]
Now, the size of the original piece of metal :-
[tex]\dfrac{9}{16}+\dfrac{15}{4}\text{ inches}\\\\=\dfrac{9+15(4)}{16}\text{ inches}\\\\=\dfrac{69}{16}\text{ inches}=4\dfrac{5}{16}\text{ inches}[/tex]
Hence, the size of the original piece of metal was [tex]4\dfrac{5}{16}\text{ inches}[/tex]
