Respuesta :
x^2+bx +16=0 is x=4
x^2+bx +16=(x-4)^2
x^2+bx +16=(x^2 -8x+16)
b=-8
Answer:
The value of b=-8
Step-by-step explanation:
Given : The only solution for the equation [tex]x^2+bx +16=0[/tex] is x=4.
To find : What is the value of b ?
Solution :
The equation [tex]x^2+bx +16=0[/tex]
The only solution of the equation is x=4.
So, Substitute the value of x in the equation
[tex](4)^2+b(4) +16=0[/tex]
[tex]16+4b+16=0[/tex]
[tex]4b+32=0[/tex]
[tex]4b=-32[/tex]
[tex]b=-\frac{32}{4}[/tex]
[tex]b=-8[/tex]
Therefore, the value of b is -8.