Respuesta :

x^2+bx +16=0 is x=4

x^2+bx +16=(x-4)^2

x^2+bx +16=(x^2 -8x+16)

b=-8

Answer:

The value of b=-8

Step-by-step explanation:

Given : The only solution for the equation [tex]x^2+bx +16=0[/tex] is x=4.

To find : What is the value of b ?

Solution :

The equation [tex]x^2+bx +16=0[/tex]

The only solution of the equation is x=4.

So, Substitute the value of x in the equation

[tex](4)^2+b(4) +16=0[/tex]

[tex]16+4b+16=0[/tex]

[tex]4b+32=0[/tex]

[tex]4b=-32[/tex]

[tex]b=-\frac{32}{4}[/tex]

[tex]b=-8[/tex]

Therefore, the value of b is -8.