Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving
∆ABC A(11, 6),
B(5, 6), and C(5, 17)
AB = 6 units BC = 11 units AC = 12.53 units
∆XYZ X(-10, 5), Y(-12, -2), and Z(-4, 15)
XY = 7.14 units YZ = 18.79 units XZ = 11.66 units
∆MNO M(-9, -4), N(-3, -4), and O(-3, -15).