Respuesta :
Answer by JKismyhusbandbae: -12 ≤ f ≤ 6
-3f - 9|-8+8 ≤ 19 + 8
|-3f-9|≤ 27
-3f-9≤ 27 and -3f - 9≥ 27
-3f-9+9≤27+9
-3f ≤ 36
(-3f) (-1) ≥ 36 (-1)3f ≥ - 36
[tex]\frac{3f}{3}[/tex] ≥ [tex]\frac{-36}{3}[/tex]
f ≥ - 12-3f
-9+9≥-27+9
-3f≥-18
[tex]\frac{3f}{3}[/tex] ≤ [tex]\frac{18}{3}[/tex]
F ≤ 6
Remark
Just as an aside, we would answer this if only 10 points were offered.
| - 3f - 9 | - 8 ≤ 19 Add 8 to both sides.
| - 3f - 9 | - 8 + 8 ≤ 19 + 8
| - 3f - 9 | ≤ 27
First Solution
- 3f - 9 ≤ 27 Add 9 to both sides
- 3f - 9 + 9 ≤ 27 + 9 Combine the terms on the left
- 3f ≤ 36 Divide by - 3. Be careful about handling the ≤ sign
f ≥ 36/-3 Do the division
f ≥ - 12
Second Solution
- 3f - 9 ≥ - 27 Add 9 to both sides.
-3f - 9 + 9 ≥ - 27 + 9
- 3f ≥ - 18
f ≤ - 18/-3
f ≤ 6
The solution set to this is the set of values between 6 and - 12
6 ≥ f and f ≥ - 12 <<<<<< Answer
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