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1. Solve for x: |-8x + 24| - 7 < 41

Respuesta :

Answer by JKismyhusbandbae: -3 < x < 9

|-8x + 24| -7 + 7 < 41 + 7

|-8x + 24| < 48

-8x + 24 < 48 and -8x + 24 > -48

-8x + 24 - 24 < 48 - 24

-8x < 24

(-8x) (-1) > 24 (-1)

[tex]\frac{8x}{8} > \frac{-24}{8}[/tex]

x >-3

-8x + 24 - 24 > -48 - 24

-8x>-72

(-8x) (-1) < (-72) (-1)

8x<72

[tex]\frac{8x}{8} < \frac{72}{8}[/tex]

x < 9

apologiabiology

for |a|<b, solve -b<a<b

|-8x+24|-7<41

add 7 to both sides

|-8x+24|<48

|a|<b so solve -b<a<b

-48<-8x+24<48

minus 24 from everybody

-72<-8x<24

divide both sides by -8, remember to flip the direction of sign since you are dividing by a negative

9>x>-3

-3<x<9 is the solution

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