Respuesta :
Given:
Moles of Al = 0.4
Moles of O2 = 0.4
To determine:
Moles of Al2O3 produced
Explanation:
4Al + 3O2 → 2Al2O3
Based on the reaction stoichiometry:
4 moles of Al produces 2 moles of Al2O3
Therefore, 0.4 moles of Al will produce:
0.4 moles Al * 2 moles Al2O3/4 moles Al = 0.2 moles Al2O3
Similarly;
3 moles O2 produces 2 moles Al2O3
0.4 moles of O2 will yield: 0.4 *2/3 = 0.267 moles
Thus Al will be the limiting reactant.
Ans: Maximum moles of Al2O3 = 0.2 moles
Answer:
There can 0.2 moles Al2O3 be produced
Explanation:
Step 1: Data given
Moles of Al = 0.4 moles
Moles of O2 = 0.4 moles
Step 2: The balanced equation
4Al + 3O2 → 2Al2O3
Step 3: Calculate the limiting reactant
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
Al is the limiting reactant. It will completely be consumed. (0.4 moles).
O2 is in excess. Therer ill react 3/4*0.4 = 0.3 moles O2
There will remain 0.4 -0.3 = 0.1 mol
Step 4: Calculate moles of Al2O3
For 4 moles Al we need 3 moles O2 to produce 2 moles Al2O3
For 0.4 moles Al we'll have 0.4/2 = 0.2 moles Al2O3
There can 0.2 moles Al2O3 be produced
