Answer:
c) RbBr.
Explanation:
Hello,
In this case, since rubidium is in group IA, one electron will be eligible to pair during a chemical reaction. In addition, as long as bromine is in group VIIA, when pairing with a metal, just one electron is eligible to pair as well. Now, based on the aforesaid facts, we infer that the undergoing chemical reaction will be:
[tex]2Rb(s)+Br_2(g)-->2RbBr[/tex]
So the formed product is [tex]RbBr[/tex] which is rubidium bromide, that is the c) answer.
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