the distance bewteen points (x1,y1) and (x2,y2) is
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
given (5,14) and (18,3)
[tex]d=\sqrt{(18-5)^2+(3-14)^2}[/tex]
[tex]d=\sqrt{(13)^2+(-11)^2}[/tex]
[tex]d=\sqrt{169+121}[/tex]
[tex]d=\sqrt{290}[/tex]
the distance between those points is √290
The distance between the points (5,14) and (18,3) is [tex]\sqrt{290}[/tex].
We have to determine, the distance between the points (5,14) and (18,3).
To find the distance between two points is determined by the distance formula given below.
The coordinates of point A are [tex](x_1, y_1)[/tex] and of B are [tex](x_2, y_2)[/tex] .
Then the formula to seek out the space/distance between two points AB is given by:
[tex]AB = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2[/tex]
Therefore,
The distance between the points (5,14) and (18,3) is,
[tex]Distance = \sqrt{(18-5)^2 + (3-14)^2}\\\\Distance = \sqrt{(13)^2 + (-11)^2}\\\\ Distance = \sqrt{169+ 121}\\\\ Distance = \sqrt{290}\\\\[/tex]
Hence, The distance between the points (5,14) and (18,3) is [tex]\sqrt{290}[/tex].
To know more about the Distance formula click the link given below.
https://brainly.com/question/12431044
