A sneaker company can make 50 pairs of sneakers for every 6 yards of material.
Then in each case you can consider proportion.
1. 50 pairs -- 6 yards,
80 pairs -- x yards.
Mathematically,
[tex]\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.[/tex]
2. 50 pairs -- 6 yards,
100 pairs -- x yards.
Mathematically,
[tex]\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.[/tex]
3. 50 pairs -- 6 yards,
120 pairs -- x yards.
Mathematically,
[tex]\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.[/tex]
4. 50 pairs -- 6 yards,
140 pairs -- x yards.
Mathematically,
[tex]\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.[/tex]
Thus, the table is
[tex]\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}[/tex]
The domain of the relation is the set [tex]\{50,80,100,120,140\}[/tex] and the range of the relation is [tex]\{6,9.6,12,14.4,16.8\}.[/tex]See attached diagram for the graph of the relation.
