Respuesta :
Hey there!:
Given the mass of PbCl(OH) :
0.135 Kg = 0.135 Kg*(1000g / 1Kg) = 135 g
Molecular mass of PbCl(OH) = 207+35.5+16+1 = 259.5 g / mol
Atomic mass of Pb = 207 g/mol
Hence mass of Pb in 135 g PbCl(OH) :
(207 g Pb / 259.5 g PbClOH) * 135g PbClOH =
0.79768 * 135 => 107.68 g of Pb
For Pb2Cl2CO3 :
Given the mass of Pb2Cl2CO3 :
0.135 Kg = 0.135 Kgx(1000g / 1Kg) = 135 g
Molecular mass of Pb2Cl2CO3 = 2*207+2*35.5+12+3*16 = 545 g / mol
Mass of Pb present in 1 mol (=545 g / mol) of Pb2Cl2CO3 = 2*207 = 414 g
Hence mass of Pb in 135 g Pb2Cl2CO3:
(414 g Pb / 545 g PbClOH) * 135g PbClOH =
0.75963 * 135 => 102.55 g of Pb2Cl2CO3
Hope that helps!
Answer: Mass of lead in [tex]PbCl(OH)[/tex] is 107.74 g and mass of lead in [tex]Pb_2Cl_2CO_3[/tex] is 103.6 g
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
- For PbCl(OH):
Given mass of PbCl(OH) = 0.135 kg = 135 g (Conversion factor: 1 kg = 1000 g)
Molar mass of PbCl(OH) = 259.66 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of PbCl(OH)}=\frac{135g}{259.66g/mol}=0.52mol[/tex]
In 1 mole of PbCl(OH), 1 mole of lead, 1 mole of chlorine, 1 mole of hydrogen and 1 mole of oxygen atoms are present.
Moles of lead = [tex](1\times 0.52)=0.52mol[/tex]
Calculating the mass of lead in PbCl(OH) by using equation 1, we get:
Molar mass of lead atom = 207.2 g/mol
Moles of lead atom = 0.52 moles
Putting values in equation 1, we get:
[tex]0.52mol=\frac{\text{Mass of lead atom}}{207.2g/mol}\\\\\text{Mass of lead atom}=107.74g[/tex]
Mass of lead atom = 107.74 g
- For [tex]Pb_2Cl_2CO_3[/tex]:
Given mass of [tex]Pb_2Cl_2CO_3[/tex] = 0.135 kg = 135 g
Molar mass of [tex]Pb_2Cl_2CO_3[/tex] = 545.3 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of }Pb_2Cl_2CO_3=\frac{135g}{545.3g/mol}=0.25mol[/tex]
In 1 mole of [tex]Pb_2Cl_2CO_3[/tex], 2 moles of lead, 2 moles of chlorine, 1 mole of carbon and 3 moles of oxygen atoms are present.
Moles of lead = [tex](2\times 0.25)=0.50mol[/tex]
Calculating the mass of lead in [tex]Pb_2Cl_2CO_3[/tex] by using equation 1, we get:
Molar mass of lead atom = 207.2 g/mol
Moles of lead atom = 0.50 moles
Putting values in equation 1, we get:
[tex]0.50mol=\frac{\text{Mass of lead atom}}{207.2g/mol}\\\\\text{Mass of lead atom}=103.6g[/tex]
Mass of lead atom = 103.6 g
Hence, mass of lead in [tex]PbCl(OH)[/tex] is 107.74 g and mass of lead in [tex]Pb_2Cl_2CO_3[/tex] is 103.6 g
