The Reactance of a Capacitor is the resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. This is measured in ohms (Ω) and its formula is:
[tex]X_{C}=\frac{1}{2\pi fC}[/tex] (1)
Where:
[tex]X_{C}[/tex] is the Reactance in ohms (Ω)
[tex]f[/tex] is the frequency of the alternating current in Hertz ([tex]Hz[/tex])
[tex]C[/tex] is the Capacitance of the Capacitor in Farad ([tex]F[/tex])
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note [tex]1mF=1*10^{-3}F=0.001F[/tex]
Well, with the given data we have to solve (1):
[tex]X_{C}=\frac{1}{2\pi(400Hz)(25*10^{-3}F)}[/tex]
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
