For the faculty we have 10 choose 4 and for the students we have 14 choose 5, so total combinations of
[tex]\displaystyle {10 \choose 4}{14 \choose 5} = \dfrac{10 \cdot 9\cdot 8 \cdot 7}{4 \cdot 3 \cdot 2 \cdot 1} \cdot \dfrac{14 \cdot 13\cdot 12 \cdot 11 \cdot 10}{5 \cdot 4 \cdot 3 \cdot 2 \cdot 1}[/tex]
[tex] \quad= ( 10(3)(1)(7) )(14(13)(1)(11)(1)) = 210(2002) = 420420[/tex]
Answer: 420,420
Answer:
25C4= (25!)/(4!*(25-4)!)=(25!)/4!*21!= (21!* 22*23*24*25)/(1*2*3*4*21!)= 12650
Step-by-step explanation:
