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A crate is pulled to the right with a force of 83.6 N, to the left with a force of 121.7 N, upward with a force of 633.6 N, and downward with a force of 241.7 N. What is the net external force in the x direction?

Respuesta :

We can assume here that left and right directions are -X and + X directions respectively

Similarly its perpendicular directions are +Y and -Y i.e. upwards and downwards respectively

So here it is given that

[tex]F_1 = 83.6 N[/tex] +X direction

[tex]F_2 = 121.7 N[/tex] - X direction

[tex]F_3 = 633.6 N[/tex] + Y direction

[tex]F_4 = 241.7 N[/tex] - Y direction

Now net force in X direction is required here in this question

So here in X direction there are two forces opposite to each other

so in order to find net force we need to add them vector addition rule

so here

[tex]F_{net} = F_1 - F_2[/tex]

[tex]F_{net} = 83.6 - 121.7[/tex]

[tex]F_{net} = -38.1 N[/tex]

so it requires 38.1 N force towards left

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