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OmegaAzzy

X is less than or equal to 2.

3x - 6 + 2 ≥ 5x - 8

Subtract 3x from both sides.

-6 + 2 ≥ 2x - 8

Combine like terms.

-4 ≥ 2x - 8

Add 8 to both sides.

4 ≥ 2x

Divide both sides by 2.

x ≤ 2


Cricetus

The solution set will be "[tex]x \leq 2[/tex]".

Let,

  • The number be "x".

According to the question,

The expression will be:

  • [tex]3x-6+2 \geq 5x-8[/tex]

By solving the expression, we get

→         [tex]3x-4 \geq 5x-8[/tex]

By subtracting "3x" from both sides, we get

→ [tex]3x-4-3x \geq 5x-8-3x[/tex]

→               [tex]-4 \geq 2x-8[/tex]

By adding "8" both sides, we get

→         [tex]-4 +8 \geq 2x-8+8[/tex]

→                 [tex]4 \geq 2x[/tex]

→                 [tex]x \leq \frac{4}{2}[/tex]

→                 [tex]x \leq 2[/tex]

Thus the above answer is right.

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